Simultaneous Showdown
Two equations face off, one answer settles it. Line up the coefficients, eliminate a variable, and find the single pair of values that solves both — the exact point where the two lines cross.
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Simultaneous Showdown 🤠
**Simultaneous equations** are two equations that share the **same** two unknowns. The solution is the one pair of values (x, y) that makes **both** true at once. The classic method is **elimination**: get rid of one variable so you can solve for the other. Time for the showdown.
The elimination idea ⚖️
If a variable has the **same coefficient** in both equations, you can remove it by adding or subtracting the equations. Take **x + y = 5** and **x − y = 1**. The y terms are +y and −y — opposites — so **adding** the equations cancels y: (x + y) + (x − y) = 5 + 1, giving 2x = 6.
Worked example 📋
Solving **x + y = 5** and **x − y = 1**: 1. **Add** the equations: 2x = 6, so **x = 3**. 2. **Back-substitute** into x + y = 5: 3 + y = 5, so **y = 2**. 3. **Check** in the other equation: 3 − 2 = 1. ✓\n\nThe solution is x = 3, y = 2.
Order the method
An interactive activity.
Solve for x
An interactive activity.
Solve for y
An interactive activity.
Add or subtract? ➗
Which operation eliminates the variable depends on the **signs** of its matching coefficients: • **Same sign** (both +y, or both −y) → **subtract** the equations. • **Opposite signs** (+y and −y) → **add** the equations. A quick memory aid: **S**ame **S**ubtract. If the coefficients do not match yet, multiply an equation through first to make them match.
Which operation?
For 2x + y = 7 and x − y = 2, you want to eliminate y. The y terms are +y and −y. Do you add or subtract the equations?
- Add them — the signs are opposite, so adding cancels y
- Subtract them
- Multiply the two equations together
- Neither — solve each on its own
Check the solution
The solution to x + y = 5 and x − y = 1 is x = 3, y = 2. Pick the TWO statements that show it is correct.
- x + y = 5 works: 3 + 2 = 5
- x − y = 1 works: 3 − 2 = 1
- x + y = 6 works: 3 + 2 = 6
- The solution is really x = 2, y = 3
The graphical showdown 📉
Each linear equation is a **straight line**. The solution to a pair of simultaneous equations is exactly the **point where the two lines cross** — the one (x, y) that lies on both. For x + y = 5 and x − y = 1, the lines cross at (3, 2) — the same answer elimination gave.
Plot the solution
An interactive activity.
The showdown rules
To solve linear simultaneous equations by elimination, make one variable's _____ match, then add or subtract to remove it. On a graph, the solution is the point where the two lines _____. Always _____ your answer in both equations.